文章目录
概述
从类的继承图上我们可知道,ArrayList实现了List接口。
-
同时List是顺序容器,即元素存放的数据与放进去的顺序相同,允许放入null元素,
-
ArrayList底层基于数组实现。
-
每个ArrayList都有一个容量(capacity),表示底层数组的实际大小,容器内存储元素的个数不能多于当前容量。
-
当向容器中添加元素时,如果容量不足,容器自动扩容。
-
ArrayList<E>
,可以看到是泛型类型, Java泛型只是编译器提供的语法糖,数组是一个Object数组,可以容纳任何类型的对象。
方法的执行效率
-
size(), isEmpty(), get(), set()
方法均能在常数时间内完成 -
add()
方法的时间开销跟插入位置有关 -
addAll()
方法的时间开销跟添加元素的个数成正比。 - 其余方法大都是线性时间。
为追求效率,ArrayList没有实现同步(synchronized),如果需要多个线程并发访问,用户可以手动同步,也可使用Vector替代
源码剖析
底层数据结构 -数组
构造函数
/**
* Constructs an empty list with the specified initial capacity.
*
* @param initialCapacity the initial capacity of the list
* @throws IllegalArgumentException if the specified initial capacity
* is negative
*/
public ArrayList(int initialCapacity) {
if (initialCapacity > 0) {
this.elementData = new Object[initialCapacity];
} else if (initialCapacity == 0) {
this.elementData = EMPTY_ELEMENTDATA;
} else {
throw new IllegalArgumentException("Illegal Capacity: "+
initialCapacity);
}
}
/**
* Constructs an empty list with an initial capacity of ten.
*/
public ArrayList() {
this.elementData = DEFAULTCAPACITY_EMPTY_ELEMENTDATA;
}
/**
* Constructs a list containing the elements of the specified
* collection, in the order they are returned by the collection's
* iterator.
*
* @param c the collection whose elements are to be placed into this list
* @throws NullPointerException if the specified collection is null
*/
public ArrayList(Collection<? extends E> c) {
Object[] a = c.toArray();
if ((size = a.length) != 0) {
if (c.getClass() == ArrayList.class) {
elementData = a;
} else {
elementData = Arrays.copyOf(a, size, Object[].class);
}
} else {
// replace with empty array.
elementData = EMPTY_ELEMENTDATA;
}
}
演示如下:
/**
* 初始化的时候指定容量
*/
List list = new ArrayList<>(1);
list.add(1);
list.add(2);
System.out.println(list.size());
/**
* 默认构造函数 ,数组大小为0
*/
list = new ArrayList();
list.add("artisan");
list.add("review");
list.add("java");
System.out.println(list.size());
/**
* 使用集合初始化一个ArrayList
*/
list = new ArrayList(Arrays.asList("I" , "Love" ,"Code"));
System.out.println(list.size());
自动扩容机制
-
每当向数组中添加元素时,都需要检查添加后元素的个数是否会超出当前数组的长度,如果超出,数组将会进行扩容,以满足添加数据的需求。
-
数组进行扩容时,会将老数组中的元素重新拷贝一份到新的数组中,每次数组容量的增长大约是其原容量的1.5倍。
这种操作的代价是很高的,因此在实际使用时,我们应该尽量避免数组容量的扩张。当我们可预知要保存的元素的多少时,要在构造ArrayList实例时,就指定其容量,以避免数组扩容的发生。
或者根据实际需求,通过调用ensureCapacity方法来手动增加ArrayList实例的容量。
ArrayList#ensureCapacity(int minCapacity)
暴漏了public方法可以允许程序猿手工扩容增加ArrayList实例的容量,以减少递增式再分配的数量。
我们来看下效率对比
/**
* 扩容对比
*/
long begin = System.currentTimeMillis();
// 初始化1亿的数据量
final int number = 100000000 ;
Object o = new Object();
ArrayList list1 = new ArrayList<String>();
for (int i = 0; i < number; i++) {
list1.add(o);
}
System.out.println("依赖ArrayList的自动扩容机制,添加数据耗时:" +(System.currentTimeMillis() - begin));
begin = System.currentTimeMillis();
ArrayList list2 = new ArrayList<String>();
// 手工扩容
list2.ensureCapacity(number);
for (int i = 0; i < number; i++) {
list2.add(o);
}
System.out.println("手工ensureCapacity扩容后,添加数据耗时:" + (System.currentTimeMillis() - begin));
原因是因为,第一段如果没有一次性扩到想要的最大容量的话,它就会在添加元素的过程中,一点一点的进行扩容,要知道对数组扩容是要进行数组拷贝的,这就会浪费大量的时间。如果已经预知容器可能会装多少元素,最好显示的调用ensureCapacity这个方法一次性扩容到位。
过程图如下:
set()
底层是一个数组, 那ArrayList的set()方法也就是直接对数组的指定位置赋值
/**
* Replaces the element at the specified position in this list with
* the specified element.
*
* @param index index of the element to replace
* @param element element to be stored at the specified position
* @return the element previously at the specified position
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public E set(int index, E element) {
rangeCheck(index);
E oldValue = elementData(index);
elementData[index] = element;
return oldValue;
}
get
get()方法也很简单,需要注意的是由于底层数组是Object[],得到元素后需要进行类型转换。
/**
* Returns the element at the specified position in this list.
*
* @param index index of the element to return
* @return the element at the specified position in this list
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public E get(int index) {
rangeCheck(index);
return elementData(index);
}
@SuppressWarnings("unchecked")
E elementData(int index) {
return (E) elementData[index];
}
add()/addAll()
这两个方法都是向容器中添加新元素,这可能会导致capacity不足,因此在添加元素之前,都需要进行剩余空间检查,如果需要则自动扩容。扩容操作最终是通过grow()方法完成的
/**
* Appends the specified element to the end of this list.
*
* @param e element to be appended to this list
* @return <tt>true</tt> (as specified by {@link Collection#add})
*/
public boolean add(E e) {
ensureCapacityInternal(size + 1); // Increments modCount!!
elementData[size++] = e;
return true;
}
/**
* Inserts the specified element at the specified position in this
* list. Shifts the element currently at that position (if any) and
* any subsequent elements to the right (adds one to their indices).
*
* @param index index at which the specified element is to be inserted
* @param element element to be inserted
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public void add(int index, E element) {
rangeCheckForAdd(index);
ensureCapacityInternal(size + 1); // Increments modCount!!
System.arraycopy(elementData, index, elementData, index + 1,
size - index);
elementData[index] = element;
size++;
}
- add(E e) 在末尾添加
- add(int index, E e)需要先对元素进行移动,然后完成插入操作,也就意味着该方法有着线性的时间复杂度。
-
addAll()方法能够一次添加多个元素,根据位置不同也有两个把本
一个是在末尾添加的
addAll(Collection<? extends E> c)
方法,一个是从指定位置开始插入的
addAll(int index, Collection<? extends E> c)
方法。跟add()方法类似,在插入之前也需要进行空间检查,如果需要则自动扩容;如果从指定位置插入,也会存在移动元素的情况。]
addAll()的时间复杂度不仅跟插入元素的多少有关,也跟插入的位置相关。
/**
* Appends all of the elements in the specified collection to the end of
* this list, in the order that they are returned by the
* specified collection's Iterator. The behavior of this operation is
* undefined if the specified collection is modified while the operation
* is in progress. (This implies that the behavior of this call is
* undefined if the specified collection is this list, and this
* list is nonempty.)
*
* @param c collection containing elements to be added to this list
* @return <tt>true</tt> if this list changed as a result of the call
* @throws NullPointerException if the specified collection is null
*/
public boolean addAll(Collection<? extends E> c) {
Object[] a = c.toArray();
int numNew = a.length;
ensureCapacityInternal(size + numNew); // Increments modCount
System.arraycopy(a, 0, elementData, size, numNew);
size += numNew;
return numNew != 0;
}
/**
* Inserts all of the elements in the specified collection into this
* list, starting at the specified position. Shifts the element
* currently at that position (if any) and any subsequent elements to
* the right (increases their indices). The new elements will appear
* in the list in the order that they are returned by the
* specified collection's iterator.
*
* @param index index at which to insert the first element from the
* specified collection
* @param c collection containing elements to be added to this list
* @return <tt>true</tt> if this list changed as a result of the call
* @throws IndexOutOfBoundsException {@inheritDoc}
* @throws NullPointerException if the specified collection is null
*/
public boolean addAll(int index, Collection<? extends E> c) {
rangeCheckForAdd(index);
Object[] a = c.toArray();
int numNew = a.length;
ensureCapacityInternal(size + numNew); // Increments modCount
int numMoved = size - index;
if (numMoved > 0)
System.arraycopy(elementData, index, elementData, index + numNew,
numMoved);
System.arraycopy(a, 0, elementData, index, numNew);
size += numNew;
return numNew != 0;
}
remove()
remove()方法也有两个方法
- 一个是remove(int index)删除指定位置的元素
- 一个是remove(Object o)删除第一个满足o.equals(elementData[index])的元素
/**
* Removes the element at the specified position in this list.
* Shifts any subsequent elements to the left (subtracts one from their
* indices).
*
* @param index the index of the element to be removed
* @return the element that was removed from the list
* @throws IndexOutOfBoundsException {@inheritDoc}
*/
public E remove(int index) {
rangeCheck(index);
modCount++;
E oldValue = elementData(index);
int numMoved = size - index - 1;
if (numMoved > 0)
System.arraycopy(elementData, index+1, elementData, index,
numMoved);
elementData[--size] = null; // clear to let GC do its work
return oldValue;
}
删除操作是add()操作的逆过程,需要将删除点之后的元素向前移动一个位置。需要注意的是为了让GC起作用,必须显式的为最后一个位置赋null值。
上面代码中如果不手动赋null值,除非对应的位置被其他元素覆盖,否则原来的对象就一直不会被回收。
/**
* Removes the first occurrence of the specified element from this list,
* if it is present. If the list does not contain the element, it is
* unchanged. More formally, removes the element with the lowest index
* <tt>i</tt> such that
* <tt>(o==null ? get(i)==null : o.equals(get(i)))</tt>
* (if such an element exists). Returns <tt>true</tt> if this list
* contained the specified element (or equivalently, if this list
* changed as a result of the call).
*
* @param o element to be removed from this list, if present
* @return <tt>true</tt> if this list contained the specified element
*/
public boolean remove(Object o) {
if (o == null) {
for (int index = 0; index < size; index++)
if (elementData[index] == null) {
fastRemove(index);
return true;
}
} else {
for (int index = 0; index < size; index++)
if (o.equals(elementData[index])) {
fastRemove(index);
return true;
}
}
return false;
}
trimToSize()
将底层数组的容量调整为当前列表保存的实际元素的大小
/**
* Trims the capacity of this <tt>ArrayList</tt> instance to be the
* list's current size. An application can use this operation to minimize
* the storage of an <tt>ArrayList</tt> instance.
*/
public void trimToSize() {
modCount++;
if (size < elementData.length) {
elementData = (size == 0)
? EMPTY_ELEMENTDATA
: Arrays.copyOf(elementData, size);
}
}
indexOf(), lastIndexOf()
获取元素的第一次出现的index
/**
* Returns the index of the first occurrence of the specified element
* in this list, or -1 if this list does not contain the element.
* More formally, returns the lowest index <tt>i</tt> such that
* <tt>(o==null ? get(i)==null : o.equals(get(i)))</tt>,
* or -1 if there is no such index.
*/
public int indexOf(Object o) {
if (o == null) {
for (int i = 0; i < size; i++)
if (elementData[i]==null)
return i;
} else {
for (int i = 0; i < size; i++)
if (o.equals(elementData[i]))
return i;
}
return -1;
}
获取元素的最后一次出现的index
/**
* Returns the index of the last occurrence of the specified element
* in this list, or -1 if this list does not contain the element.
* More formally, returns the highest index <tt>i</tt> such that
* <tt>(o==null ? get(i)==null : o.equals(get(i)))</tt>,
* or -1 if there is no such index.
*/
public int lastIndexOf(Object o) {
if (o == null) {
for (int i = size-1; i >= 0; i--)
if (elementData[i]==null)
return i;
} else {
for (int i = size-1; i >= 0; i--)
if (o.equals(elementData[i]))
return i;
}
return -1;
}
Fail-Fast
ArrayList同样采用了快速失败的机制,通过记录modCount参数来实现。在面对并发的修改时,迭代器很快就会完全失败,而不是冒着在将来某个不确定时间发生任意不确定行为的风险。
具体参考前段时间写的一篇博文如下:
本文摘自 :https://blog.51cto.com/u