当前位置:首页 > IT技术 > 编程语言 > 正文

Java Review - ArrayList 源码解读
2021-11-16 11:28:04

Java Review - ArrayList 源码解读_ArrayList


概述

Java Review - ArrayList 源码解读_i++_02

从类的继承图上我们可知道,ArrayList实现了List接口。

  • 同时List是顺序容器,即元素存放的数据与放进去的顺序相同,允许放入null元素,

  • ArrayList底层基于数组实现。

  • 每个ArrayList都有一个容量(capacity),表示底层数组的实际大小,容器内存储元素的个数不能多于当前容量。

  • 当向容器中添加元素时,如果容量不足,容器自动扩容。

  • ArrayList<E>,可以看到是泛型类型, Java泛型只是编译器提供的语法糖,数组是一个Object数组,可以容纳任何类型的对象。
    Java Review - ArrayList 源码解读_添加数据_03

Java Review - ArrayList 源码解读_i++_04


方法的执行效率

Java Review - ArrayList 源码解读_i++_05

  • size(), isEmpty(), get(), set()方法均能在常数时间内完成
  • add()方法的时间开销跟插入位置有关
  • addAll()方法的时间开销跟添加元素的个数成正比。
  • 其余方法大都是线性时间。

为追求效率,ArrayList没有实现同步(synchronized),如果需要多个线程并发访问,用户可以手动同步,也可使用Vector替代


源码剖析

底层数据结构 -数组

Java Review - ArrayList 源码解读_ArrayList_06


构造函数

Java Review - ArrayList 源码解读_ArrayList_07

  /**
     * Constructs an empty list with the specified initial capacity.
     *
     * @param  initialCapacity  the initial capacity of the list
     * @throws IllegalArgumentException if the specified initial capacity
     *         is negative
     */
    public ArrayList(int initialCapacity) {
        if (initialCapacity > 0) {
            this.elementData = new Object[initialCapacity];
        } else if (initialCapacity == 0) {
            this.elementData = EMPTY_ELEMENTDATA;
        } else {
            throw new IllegalArgumentException("Illegal Capacity: "+
                                               initialCapacity);
        }
    }

    /**
     * Constructs an empty list with an initial capacity of ten.
     */
    public ArrayList() {
        this.elementData = DEFAULTCAPACITY_EMPTY_ELEMENTDATA;
    }

    /**
     * Constructs a list containing the elements of the specified
     * collection, in the order they are returned by the collection's
     * iterator.
     *
     * @param c the collection whose elements are to be placed into this list
     * @throws NullPointerException if the specified collection is null
     */
    public ArrayList(Collection<? extends E> c) {
        Object[] a = c.toArray();
        if ((size = a.length) != 0) {
            if (c.getClass() == ArrayList.class) {
                elementData = a;
            } else {
                elementData = Arrays.copyOf(a, size, Object[].class);
            }
        } else {
            // replace with empty array.
            elementData = EMPTY_ELEMENTDATA;
        }
    }

Java Review - ArrayList 源码解读_添加数据_08

演示如下:


        /**
         * 初始化的时候指定容量
         */
        List list = new ArrayList<>(1);
        list.add(1);
        list.add(2);
        System.out.println(list.size());

        /**
         * 默认构造函数 ,数组大小为0
         */
        list = new ArrayList();
        list.add("artisan");
        list.add("review");
        list.add("java");
        System.out.println(list.size());



        /**
         * 使用集合初始化一个ArrayList
         */
        list = new ArrayList(Arrays.asList("I" , "Love" ,"Code"));
        System.out.println(list.size());



自动扩容机制

  • 每当向数组中添加元素时,都需要检查添加后元素的个数是否会超出当前数组的长度,如果超出,数组将会进行扩容,以满足添加数据的需求。
    Java Review - ArrayList 源码解读_ArrayList_09

  • 数组进行扩容时,会将老数组中的元素重新拷贝一份到新的数组中,每次数组容量的增长大约是其原容量的1.5倍。

    这种操作的代价是很高的,因此在实际使用时,我们应该尽量避免数组容量的扩张。当我们可预知要保存的元素的多少时,要在构造ArrayList实例时,就指定其容量,以避免数组扩容的发生。

    或者根据实际需求,通过调用ensureCapacity方法来手动增加ArrayList实例的容量。

Java Review - ArrayList 源码解读_添加数据_10

  • ArrayList#ensureCapacity(int minCapacity)暴漏了public方法可以允许程序猿手工扩容增加ArrayList实例的容量,以减少递增式再分配的数量。

我们来看下效率对比

 /**
         * 扩容对比
         */

        long begin = System.currentTimeMillis();
        // 初始化1亿的数据量
        final int number = 100000000 ;
        Object o = new Object();
        ArrayList list1 = new ArrayList<String>();
        for (int i = 0; i < number; i++) {
            list1.add(o);
        }
        System.out.println("依赖ArrayList的自动扩容机制,添加数据耗时:" +(System.currentTimeMillis() - begin));


        begin = System.currentTimeMillis();
        ArrayList list2 = new ArrayList<String>();
        // 手工扩容
        list2.ensureCapacity(number);
        for (int i = 0; i < number; i++) {
            list2.add(o);
        }
        System.out.println("手工ensureCapacity扩容后,添加数据耗时:" + (System.currentTimeMillis() - begin));


Java Review - ArrayList 源码解读_i++_11
原因是因为,第一段如果没有一次性扩到想要的最大容量的话,它就会在添加元素的过程中,一点一点的进行扩容,要知道对数组扩容是要进行数组拷贝的,这就会浪费大量的时间。如果已经预知容器可能会装多少元素,最好显示的调用ensureCapacity这个方法一次性扩容到位

过程图如下:

Java Review - ArrayList 源码解读_数组_12


set()

底层是一个数组, 那ArrayList的set()方法也就是直接对数组的指定位置赋值

    /**
     * Replaces the element at the specified position in this list with
     * the specified element.
     *
     * @param index index of the element to replace
     * @param element element to be stored at the specified position
     * @return the element previously at the specified position
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E set(int index, E element) {
        rangeCheck(index);

        E oldValue = elementData(index);
        elementData[index] = element;
        return oldValue;
    }

get

get()方法也很简单,需要注意的是由于底层数组是Object[],得到元素后需要进行类型转换。

  /**
     * Returns the element at the specified position in this list.
     *
     * @param  index index of the element to return
     * @return the element at the specified position in this list
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E get(int index) {
        rangeCheck(index);

        return elementData(index);
    }
  @SuppressWarnings("unchecked")
    E elementData(int index) {
        return (E) elementData[index];
    }


add()/addAll()

这两个方法都是向容器中添加新元素,这可能会导致capacity不足,因此在添加元素之前,都需要进行剩余空间检查,如果需要则自动扩容。扩容操作最终是通过grow()方法完成的

/**
     * Appends the specified element to the end of this list.
     *
     * @param e element to be appended to this list
     * @return <tt>true</tt> (as specified by {@link Collection#add})
     */
    public boolean add(E e) {
        ensureCapacityInternal(size + 1);  // Increments modCount!!
        elementData[size++] = e;
        return true;
    }

    /**
     * Inserts the specified element at the specified position in this
     * list. Shifts the element currently at that position (if any) and
     * any subsequent elements to the right (adds one to their indices).
     *
     * @param index index at which the specified element is to be inserted
     * @param element element to be inserted
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public void add(int index, E element) {
        rangeCheckForAdd(index);

        ensureCapacityInternal(size + 1);  // Increments modCount!!
        System.arraycopy(elementData, index, elementData, index + 1,
                         size - index);
        elementData[index] = element;
        size++;
    }

Java Review - ArrayList 源码解读_ArrayList_13

  • add(E e) 在末尾添加
  • add(int index, E e)需要先对元素进行移动,然后完成插入操作,也就意味着该方法有着线性的时间复杂度。

Java Review - ArrayList 源码解读_数组_14

  • addAll()方法能够一次添加多个元素,根据位置不同也有两个把本

    一个是在末尾添加的addAll(Collection<? extends E> c)方法,

    一个是从指定位置开始插入的addAll(int index, Collection<? extends E> c)方法。

    跟add()方法类似,在插入之前也需要进行空间检查,如果需要则自动扩容;如果从指定位置插入,也会存在移动元素的情况。]

    addAll()的时间复杂度不仅跟插入元素的多少有关,也跟插入的位置相关。

 /**
     * Appends all of the elements in the specified collection to the end of
     * this list, in the order that they are returned by the
     * specified collection's Iterator.  The behavior of this operation is
     * undefined if the specified collection is modified while the operation
     * is in progress.  (This implies that the behavior of this call is
     * undefined if the specified collection is this list, and this
     * list is nonempty.)
     *
     * @param c collection containing elements to be added to this list
     * @return <tt>true</tt> if this list changed as a result of the call
     * @throws NullPointerException if the specified collection is null
     */
    public boolean addAll(Collection<? extends E> c) {
        Object[] a = c.toArray();
        int numNew = a.length;
        ensureCapacityInternal(size + numNew);  // Increments modCount
        System.arraycopy(a, 0, elementData, size, numNew);
        size += numNew;
        return numNew != 0;
    }

    /**
     * Inserts all of the elements in the specified collection into this
     * list, starting at the specified position.  Shifts the element
     * currently at that position (if any) and any subsequent elements to
     * the right (increases their indices).  The new elements will appear
     * in the list in the order that they are returned by the
     * specified collection's iterator.
     *
     * @param index index at which to insert the first element from the
     *              specified collection
     * @param c collection containing elements to be added to this list
     * @return <tt>true</tt> if this list changed as a result of the call
     * @throws IndexOutOfBoundsException {@inheritDoc}
     * @throws NullPointerException if the specified collection is null
     */
    public boolean addAll(int index, Collection<? extends E> c) {
        rangeCheckForAdd(index);

        Object[] a = c.toArray();
        int numNew = a.length;
        ensureCapacityInternal(size + numNew);  // Increments modCount

        int numMoved = size - index;
        if (numMoved > 0)
            System.arraycopy(elementData, index, elementData, index + numNew,
                             numMoved);

        System.arraycopy(a, 0, elementData, index, numNew);
        size += numNew;
        return numNew != 0;
    }


remove()

remove()方法也有两个方法

  • 一个是remove(int index)删除指定位置的元素
  • 一个是remove(Object o)删除第一个满足o.equals(elementData[index])的元素
 /**
     * Removes the element at the specified position in this list.
     * Shifts any subsequent elements to the left (subtracts one from their
     * indices).
     *
     * @param index the index of the element to be removed
     * @return the element that was removed from the list
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E remove(int index) {
        rangeCheck(index);

        modCount++;
        E oldValue = elementData(index);

        int numMoved = size - index - 1;
        if (numMoved > 0)
            System.arraycopy(elementData, index+1, elementData, index,
                             numMoved);
        elementData[--size] = null; // clear to let GC do its work

        return oldValue;
    }

删除操作是add()操作的逆过程,需要将删除点之后的元素向前移动一个位置。需要注意的是为了让GC起作用,必须显式的为最后一个位置赋null值。

上面代码中如果不手动赋null值,除非对应的位置被其他元素覆盖,否则原来的对象就一直不会被回收。


    /**
     * Removes the first occurrence of the specified element from this list,
     * if it is present.  If the list does not contain the element, it is
     * unchanged.  More formally, removes the element with the lowest index
     * <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>
     * (if such an element exists).  Returns <tt>true</tt> if this list
     * contained the specified element (or equivalently, if this list
     * changed as a result of the call).
     *
     * @param o element to be removed from this list, if present
     * @return <tt>true</tt> if this list contained the specified element
     */
    public boolean remove(Object o) {
        if (o == null) {
            for (int index = 0; index < size; index++)
                if (elementData[index] == null) {
                    fastRemove(index);
                    return true;
                }
        } else {
            for (int index = 0; index < size; index++)
                if (o.equals(elementData[index])) {
                    fastRemove(index);
                    return true;
                }
        }
        return false;
    }

Java Review - ArrayList 源码解读_ArrayList_15


trimToSize()

将底层数组的容量调整为当前列表保存的实际元素的大小

  /**
     * Trims the capacity of this <tt>ArrayList</tt> instance to be the
     * list's current size.  An application can use this operation to minimize
     * the storage of an <tt>ArrayList</tt> instance.
     */
    public void trimToSize() {
        modCount++;
        if (size < elementData.length) {
            elementData = (size == 0)
              ? EMPTY_ELEMENTDATA
              : Arrays.copyOf(elementData, size);
        }
    }

indexOf(), lastIndexOf()

获取元素的第一次出现的index

   /**
     * Returns the index of the first occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the lowest index <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>,
     * or -1 if there is no such index.
     */
    public int indexOf(Object o) {
        if (o == null) {
            for (int i = 0; i < size; i++)
                if (elementData[i]==null)
                    return i;
        } else {
            for (int i = 0; i < size; i++)
                if (o.equals(elementData[i]))
                    return i;
        }
        return -1;
    }

获取元素的最后一次出现的index

    /**
     * Returns the index of the last occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the highest index <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>,
     * or -1 if there is no such index.
     */
    public int lastIndexOf(Object o) {
        if (o == null) {
            for (int i = size-1; i >= 0; i--)
                if (elementData[i]==null)
                    return i;
        } else {
            for (int i = size-1; i >= 0; i--)
                if (o.equals(elementData[i]))
                    return i;
        }
        return -1;
    }


Fail-Fast

ArrayList同样采用了快速失败的机制,通过记录modCount参数来实现。在面对并发的修改时,迭代器很快就会完全失败,而不是冒着在将来某个不确定时间发生任意不确定行为的风险。

具体参考前段时间写的一篇博文如下:

Java - Java集合中的快速失败Fail Fast 机制

Java Review - ArrayList 源码解读_添加数据_16

本文摘自 :https://blog.51cto.com/u

开通会员,享受整站包年服务立即开通 >