(1) y=
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(3) y=
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(3) y=
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 解 (1)函数的反函数是.因为反函数的定义域为x≠2,它就是原函数的值域.故所求函数的值域W=(-∞,2)∪(2,+∞).(2)y==,所以函数的值域为[2,+∞).(3)则y≤1.故函数的值域W=(-∞,1].(4)y=2-⇒2-12≤y<2,值域W=[-10,2). (本文共 145 字 , 6 张图 ) ; (2) y=;
(3) y=;(4) y=
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